1/2z^2=-5

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Solution for 1/2z^2=-5 equation: 



1/2z^2=-5

We move all terms to the left:

1/2z^2-(-5)=0



Domain of the equation: 2z^2!=0

z^2!=0/2

z^2!=√0

z!=0

z∈R



We add all the numbers together, and all the variables

1/2z^2+5=0

We multiply all the terms by the denominator


5*2z^2+1=0

Wy multiply elements

10z^2+1=0

a = 10; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·10·1
Δ = -40
Delta is less than zero, so there is no solution for the equation

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